16x^2+112x-1323=0

Solution for 16x^2+112x-1323=0 equation:

16x^2+112x-1323=0

a = 16; b = 112; c = -1323;
Δ = b2-4ac
Δ = 1122-4·16·(-1323)
Δ = 97216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{97216}=\sqrt{3136*31}=\sqrt{3136}*\sqrt{31}=56\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-56\sqrt{31}}{2*16}=\frac{-112-56\sqrt{31}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+56\sqrt{31}}{2*16}=\frac{-112+56\sqrt{31}}{32}
$